Math problems

[kitex973]

(365*8000)/3.14)/(6.67*10^-14)/100000

[jamie1990]

22

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[darkus-s6]

Is it 728??

[irecinius]

22

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You are very right, jamie!
if you go to 23, it will give you fractions~

[shautieh]

There are no problems going on ? Anyone ? (not that I have time nowadays though )

[Urameshi-sama]

^Seconded. The problems here are slowly refreshing me from my math rustiness, even if I am not among the people to get the answer first

[irecinius]

Well it was supposed to be jamie turn..

[darkus-s6]

well since nobody has posted a new problem in a while i'll go ahead with a new one:

Consider a large jar of custer sugar, an unmarked balance and a 1 gram weight. What is the minimum number of weighing operations by which 1 kg of sugar is measured, and how is that procedure.

[Volvogga]

umm... if I remember my physics correctly, it can be done in one go. You just need to place the 1 gram weight 1000 times the distance away from the fulcrum as the distance between the fulcrum and the sugar.

so... 1Kg|sugar-fulcrum-{1000x}-1g|weight

or... close enough, you get my meaning.

[adonai]

^ I'm pretty sure that it's supposed to "equal" = "balanced".

In which case it is:

1
2
4
8
16
32
64
128
256
512
1024

minus 16 and 8

So 15 measurements in total


At each step the scale is balanced and the amounts are pooled together, with the exception of 8 and 16, which are measured twice with one set put aside, this is then used in 2 more measurements to subtract 8 and 16 from 1024. So, 11 measurements to get to 1024, along with 2 extra measurements of 16 and 8, then another 2 measurements of 16 and 8 at the end (this time taken from the pool of sugar instead of the jar).