(365*8000)/3.14)/(6.67*10^-14)/100000
(365*8000)/3.14)/(6.67*10^-14)/100000
22
[[[[[[[[[[[[[[
Is it 728??
"sleep with me tonight, sweety" ~sakura_hana~
There are no problems going on ? Anyone ? (not that I have time nowadays though )
^Seconded. The problems here are slowly refreshing me from my math rustiness, even if I am not among the people to get the answer first
Stolen Sig Count: 25
Well it was supposed to be jamie turn..
"Chile is a thin and tall country"
well since nobody has posted a new problem in a while i'll go ahead with a new one:
Consider a large jar of custer sugar, an unmarked balance and a 1 gram weight. What is the minimum number of weighing operations by which 1 kg of sugar is measured, and how is that procedure.
"sleep with me tonight, sweety" ~sakura_hana~
umm... if I remember my physics correctly, it can be done in one go. You just need to place the 1 gram weight 1000 times the distance away from the fulcrum as the distance between the fulcrum and the sugar.
so... 1Kg|sugar-fulcrum-{1000x}-1g|weight
or... close enough, you get my meaning.
Vol~
thanks to Silverwmoon!
^ I'm pretty sure that it's supposed to "equal" = "balanced".
In which case it is:
1
2
4
8
16
32
64
128
256
512
1024
minus 16 and 8
So 15 measurements in total
At each step the scale is balanced and the amounts are pooled together, with the exception of 8 and 16, which are measured twice with one set put aside, this is then used in 2 more measurements to subtract 8 and 16 from 1024. So, 11 measurements to get to 1024, along with 2 extra measurements of 16 and 8, then another 2 measurements of 16 and 8 at the end (this time taken from the pool of sugar instead of the jar).
Last edited by adonai; 03-12-2008 at 03:37 PM.
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